Newton's Third Law Simulator

Action & Reaction Forces • Conservation of Momentum • Spring & Collision Physics

Action & Reaction Forces Are Equal and Opposite
✓ Forces Always Equal & Opposite
ORIGIN (x = 0) 0.0 N CART A mA = 2.0 kg 0.0 N CART B mB = 2.0 kg FA = 0 N FB = 0 N vA = 0 m/s vB = 0 m/s

Cart A Telemetry

Action Target
Instant Force: 0.0 N
Peak Force: 0.0 N
Acceleration: 0.00 m/s²
Velocity: 0.00 m/s
Momentum: 0.00 kg·m/s

Physics Equality Verification

3rd Law Proof
Action Force 0.0 N
=
Reaction Force (Opposite Direction) 0.0 N
System Total Momentum:
0.00 + 0.00 = 0.00 kg·m/s

Cart B Telemetry

Reaction Target
Instant Force: 0.0 N
Peak Force: 0.0 N
Acceleration: 0.00 m/s²
Velocity: 0.00 m/s
Momentum: 0.00 kg·m/s

Real-Time Force Sensors Pulse (Cart A vs Cart B)

Cart A Cart B

Cart Velocities over Time (Cart A vs Cart B)

Cart A Cart B

1. The Core Principle

Whenever Object A exerts a force on Object B, Object B simultaneously exerts an equal in magnitude and opposite in direction force on Object A.

Action Force = Equal & Opposite Reaction Force

2. Why Acceleration Differs

Even though the interaction forces are identical in magnitude, the resulting accelerations depend inversely on the mass of each cart.

Acceleration is Inversely Proportional to Mass

A cart with 5x the mass will experience 1/5th the acceleration!

3. Conservation of Momentum

Because the net external force on the two-cart system is zero, the total system momentum remains perfectly conserved throughout motion.

Total System Momentum = Constant

Concept Check & Self Assessment

Score: 0 / 3

Q1. If Cart A (mass = 6 kg) pushes against Cart B (mass = 2 kg), which cart experiences the greater force?

Q2. In the heavy vs light cart experiment (Cart A = 6 kg, Cart B = 1.5 kg), how will their final speeds compare after release?

Q3. What is the total sum of momentum of both carts after being released from rest?